What are the solutions to the equation x^1-x^2=0,3x^1-2x^2=-1 ?

The solutions to the equation x^1-x^2=0,3x^1-2x^2=-1 are x=0,x=1

Find the zeros of x^1-x^2=0,3x^1-2x^2=-1

The zeros of x^1-x^2=0,3x^1-2x^2=-1 are x=0,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{1} - x^{2} = 0, 3 x^{1} - 2 x^{2} = - 1

x = 0, x = 1

Solution steps

x^{1} - x^{2} = 0

Refine

x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

15 x^{2} + 7 x = 2

3 x^{2} + 12 x + 11

0 = - 3 x^{2} + 6

(3 x + 1)^{2} - (x + 4)^{2} = - 15

(x + 2)^{2} - 6 = 4 x - 2

What are the solutions to the equation x^1-x^2=0,3x^1-2x^2=-1 ?
The solutions to the equation x^1-x^2=0,3x^1-2x^2=-1 are x=0,x=1
Find the zeros of x^1-x^2=0,3x^1-2x^2=-1
The zeros of x^1-x^2=0,3x^1-2x^2=-1 are x=0,x=1