What are the solutions to the equation (x+2)^2-6=4x-2 ?

The solutions to the equation (x+2)^2-6=4x-2 are x=0

Find the zeros of (x+2)^2-6=4x-2

The zeros of (x+2)^2-6=4x-2 are x=0

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(x + 2)^{2} - 6 = 4 x - 2

x = 0

Solution steps

(x + 2)^{2} - 6 = 4 x - 2

Expand

(x + 2)^{2} - 6 : x^{2} + 4 x - 2

x^{2} + 4 x - 2 = 4 x - 2

Move

2

to the right side

x^{2} + 4 x = 4 x

Move

4 x

to the left side

x^{2} = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

x = 0

p^{2} + p = 0

4 t = t^{2}

k^{2} - 9 k + 20 = 0

x^{2} - 2.455 x + 1.25 = 0

3 x (x + 2) - 5 (x - 3) = 17

What are the solutions to the equation (x+2)^2-6=4x-2 ?
The solutions to the equation (x+2)^2-6=4x-2 are x=0
Find the zeros of (x+2)^2-6=4x-2
The zeros of (x+2)^2-6=4x-2 are x=0