What are the solutions to the equation k^2-9k+20=0 ?

The solutions to the equation k^2-9k+20=0 are k=5,k=4

Find the zeros of k^2-9k+20=0

The zeros of k^2-9k+20=0 are k=5,k=4

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k^{2} - 9 k + 20 = 0

k = 5, k = 4

Solution steps

k^{2} - 9 k + 20 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

k_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, k_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

k = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

k = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

k = 5, k = 4

x^{2} - 2.455 x + 1.25 = 0

3 x (x + 2) - 5 (x - 3) = 17

3 x^{2} - 22 x = 16

x^{2} + (3 + x)^{2} = (6 + x)^{2}

- 9 x^{2} + 2 = 0

What are the solutions to the equation k^2-9k+20=0 ?
The solutions to the equation k^2-9k+20=0 are k=5,k=4
Find the zeros of k^2-9k+20=0
The zeros of k^2-9k+20=0 are k=5,k=4