What are the solutions to the equation -9x^2+1=0 ?

The solutions to the equation -9x^2+1=0 are x= 1/3 ,x=-1/3

Find the zeros of -9x^2+1=0

The zeros of -9x^2+1=0 are x= 1/3 ,x=-1/3

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- 9 x^{2} + 1 = 0

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.33333 \dots, x = - 0.33333 \dots

Solution steps

- 9 x^{2} + 1 = 0

Move

1

to the right side

- 9 x^{2} = - 1

Divide both sides by

- 9

x^{2} = \frac{1}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{9}, x = - \frac{1}{9}

\frac{1}{9} = \frac{1}{3}

- \frac{1}{9} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

x^{2} = 1225

x, P (x - Q)^{2} + R = 0

7 x^{2} - 14 x - 56 = 0

- \frac{1}{3} x^{2} - 3 = - 2

(x + 2)^{2} = 4 (x + 2)

What are the solutions to the equation -9x^2+1=0 ?
The solutions to the equation -9x^2+1=0 are x= 1/3 ,x=-1/3
Find the zeros of -9x^2+1=0
The zeros of -9x^2+1=0 are x= 1/3 ,x=-1/3