What are the solutions to the equation -1/3 x^2-3=-2 ?

The solutions to the equation -1/3 x^2-3=-2 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of -1/3 x^2-3=-2

The zeros of -1/3 x^2-3=-2 are x=sqrt(3)i,x=-sqrt(3)i

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- \frac{1}{3} x^{2} - 3 = - 2

x = 3 i, x = - 3 i

Solution steps

- \frac{1}{3} x^{2} - 3 = - 2

Move

3

to the right side

- \frac{1}{3} x^{2} = 1

Multiply both sides by

- 3

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

(x + 2)^{2} = 4 (x + 2)

(2 x - 4)^{2} = 80

C, C^{2} = a^{2} + b^{2}

x^{2} + 6 x - 80 = 0

x^{2} - 4 = 6 x

What are the solutions to the equation -1/3 x^2-3=-2 ?
The solutions to the equation -1/3 x^2-3=-2 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of -1/3 x^2-3=-2
The zeros of -1/3 x^2-3=-2 are x=sqrt(3)i,x=-sqrt(3)i