What are the solutions to the equation 8x^2-4x+2=0 ?

The solutions to the equation 8x^2-4x+2=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4

Find the zeros of 8x^2-4x+2=0

The zeros of 8x^2-4x+2=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4

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8 x^{2} - 4 x + 2 = 0

x = \frac{1}{4} + i \frac{3}{4}, x = \frac{1}{4} - i \frac{3}{4}

Solution steps

8 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

Simplify

(- 4)^{2} - 4 \cdot 8 \cdot 2 : 43 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 3 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 3 i}{2 \cdot 8}, x_{2} = \frac{- ( - 4 ) - 4 3 i}{2 \cdot 8}

x = \frac{- ( - 4 ) + 4 3 i}{2 \cdot 8} : \frac{1}{4} + i \frac{3}{4}

x = \frac{- ( - 4 ) - 4 3 i}{2 \cdot 8} : \frac{1}{4} - i \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{3}{4}, x = \frac{1}{4} - i \frac{3}{4}

35 m^{2} + 33 m - 8 = 0

2 a^{2} - 2 a - 3 = - 2 a

2 x^{2} - 20 x = 22

- 3 x^{2} + 2 x = - 3

x^{2} + 16 x - 64 = 0

What are the solutions to the equation 8x^2-4x+2=0 ?
The solutions to the equation 8x^2-4x+2=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4
Find the zeros of 8x^2-4x+2=0
The zeros of 8x^2-4x+2=0 are x= 1/4+i(sqrt(3))/4 ,x= 1/4-i(sqrt(3))/4