What are the solutions to the equation (2y-5)*(y+4)=0 ?

The solutions to the equation (2y-5)*(y+4)=0 are y= 5/2 ,y=-4

Find the zeros of (2y-5)*(y+4)=0

The zeros of (2y-5)*(y+4)=0 are y= 5/2 ,y=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 y - 5) \cdot (y + 4) = 0

y = \frac{5}{2}, y = - 4

Decimal Notation

y = 2.5, y = - 4

Solution steps

(2 y - 5) (y + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 y - 5 = 0 or y + 4 = 0

Solve

2 y - 5 = 0 : y = \frac{5}{2}

Solve

y + 4 = 0 : y = - 4

The solutions to the quadratic equation are:

y = \frac{5}{2}, y = - 4

128 - 2 b^{2} = 0

x^{2} - 1300 x + 360000 = 0

6 x^{2} + (2 n + 3) x + n = 0

p^{2} - 41 p + 400 = 0

x, (x - 5)^{2} = 9

What are the solutions to the equation (2y-5)*(y+4)=0 ?
The solutions to the equation (2y-5)*(y+4)=0 are y= 5/2 ,y=-4
Find the zeros of (2y-5)*(y+4)=0
The zeros of (2y-5)*(y+4)=0 are y= 5/2 ,y=-4