What are the solutions to the equation 4=3x^2-x ?

The solutions to the equation 4=3x^2-x are x= 4/3 ,x=-1

Find the zeros of 4=3x^2-x

The zeros of 4=3x^2-x are x= 4/3 ,x=-1

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4 = 3 x^{2} - x

x = \frac{4}{3}, x = - 1

Decimal Notation

x = 1.33333 \dots, x = - 1

Solution steps

4 = 3 x^{2} - x

Switch sides

3 x^{2} - x = 4

Move

4

to the left side

3 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

x = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 1

d^{2} + d - 19 = 4 d

m^{2} + 11 m = - 30

x^{(2)} + 5 x + 6 = 0

x, f (a + h) = - 5 x^{2} + 2 x - 1

x, f (x)^{2} = x + 2

What are the solutions to the equation 4=3x^2-x ?
The solutions to the equation 4=3x^2-x are x= 4/3 ,x=-1
Find the zeros of 4=3x^2-x
The zeros of 4=3x^2-x are x= 4/3 ,x=-1