What are the solutions to the equation -72=-10b^2+8 ?

The solutions to the equation -72=-10b^2+8 are b=2sqrt(2),b=-2sqrt(2)

Find the zeros of -72=-10b^2+8

The zeros of -72=-10b^2+8 are b=2sqrt(2),b=-2sqrt(2)

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- 72 = - 10 b^{2} + 8

b = 22, b = - 22

Decimal Notation

b = 2.82842 \dots, b = - 2.82842 \dots

Solution steps

- 72 = - 10 b^{2} + 8

Switch sides

- 10 b^{2} + 8 = - 72

Move

8

to the right side

- 10 b^{2} = - 80

Divide both sides by

- 10

b^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 8, b = - 8

8 = 22

- 8 = - 22

b = 22, b = - 22

2 x^{2} - 11 x + 28 = x^{2}

y, 9 x^{2} + 4 y^{2} = 36

6 x^{2} - 35 = - 11 x

2 x^{2} + 7 x - 5 = 0

x, x^{2} - y - 1 = C

What are the solutions to the equation -72=-10b^2+8 ?
The solutions to the equation -72=-10b^2+8 are b=2sqrt(2),b=-2sqrt(2)
Find the zeros of -72=-10b^2+8
The zeros of -72=-10b^2+8 are b=2sqrt(2),b=-2sqrt(2)