What are the solutions to the equation solvefor y,9x^2+4y^2=36 ?

The solutions to the equation solvefor y,9x^2+4y^2=36 are y=(3sqrt(4-x^2))/2 ,y=-(3sqrt(4-x^2))/2

Find the zeros of solvefor y,9x^2+4y^2=36

The zeros of solvefor y,9x^2+4y^2=36 are y=(3sqrt(4-x^2))/2 ,y=-(3sqrt(4-x^2))/2

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solve for

y, 9 x^{2} + 4 y^{2} = 36

y = \frac{3 4 - x ^{2}}{2}, y = - \frac{3 4 - x ^{2}}{2}

Solution steps

9 x^{2} + 4 y^{2} = 36

Move

9 x^{2}

to the right side

4 y^{2} = 36 - 9 x^{2}

Divide both sides by

4

y^{2} = \frac{36 - 9 x ^{2}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{36 - 9 x ^{2}}{4}, y = - \frac{36 - 9 x ^{2}}{4}

Simplify

\frac{36 - 9 x ^{2}}{4} : \frac{3 4 - x ^{2}}{2}

Simplify

- \frac{36 - 9 x ^{2}}{4} : - \frac{3 4 - x ^{2}}{2}

y = \frac{3 4 - x ^{2}}{2}, y = - \frac{3 4 - x ^{2}}{2}

6 x^{2} - 35 = - 11 x

2 x^{2} + 7 x - 5 = 0

x, x^{2} - y - 1 = C

x, 4 x^{2} + 8 x = 21

8 (x^{2} - x) = - 2

What are the solutions to the equation solvefor y,9x^2+4y^2=36 ?
The solutions to the equation solvefor y,9x^2+4y^2=36 are y=(3sqrt(4-x^2))/2 ,y=-(3sqrt(4-x^2))/2
Find the zeros of solvefor y,9x^2+4y^2=36
The zeros of solvefor y,9x^2+4y^2=36 are y=(3sqrt(4-x^2))/2 ,y=-(3sqrt(4-x^2))/2