What are the solutions to the equation 12m^2+m-10=-4 ?

The solutions to the equation 12m^2+m-10=-4 are m= 2/3 ,m=-3/4

Find the zeros of 12m^2+m-10=-4

The zeros of 12m^2+m-10=-4 are m= 2/3 ,m=-3/4

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12 m^{2} + m - 10 = - 4

m = \frac{2}{3}, m = - \frac{3}{4}

Decimal Notation

m = 0.66666 \dots, m = - 0.75

Solution steps

12 m^{2} + m - 10 = - 4

Move

4

to the left side

12 m^{2} + m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

1^{2} - 4 \cdot 12 (- 6) = 17

m_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 12}

Separate the solutions

m_{1} = \frac{- 1 + 17}{2 \cdot 12}, m_{2} = \frac{- 1 - 17}{2 \cdot 12}

m = \frac{- 1 + 17}{2 \cdot 12} : \frac{2}{3}

m = \frac{- 1 - 17}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

m = \frac{2}{3}, m = - \frac{3}{4}

x^{2} = 14 x - 48

11 = 7 + 17 x - 16 x^{2}

(- 16 t^{2} + 60 t + 180) = 0

x^{2} - \frac{4}{3} x = 0

2 x^{2} - 1 x - 3 = 0

What are the solutions to the equation 12m^2+m-10=-4 ?
The solutions to the equation 12m^2+m-10=-4 are m= 2/3 ,m=-3/4
Find the zeros of 12m^2+m-10=-4
The zeros of 12m^2+m-10=-4 are m= 2/3 ,m=-3/4