What are the solutions to the equation t^2-19t=-90 ?

The solutions to the equation t^2-19t=-90 are t=10,t=9

Find the zeros of t^2-19t=-90

The zeros of t^2-19t=-90 are t=10,t=9

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t^{2} - 19 t = - 90

t = 10, t = 9

Solution steps

t^{2} - 19 t = - 90

Move

90

to the left side

t^{2} - 19 t + 90 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 90 = 1

t_{1, 2} = \frac{- ( - 19 ) \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 19 ) + 1}{2 \cdot 1}, t_{2} = \frac{- ( - 19 ) - 1}{2 \cdot 1}

t = \frac{- ( - 19 ) + 1}{2 \cdot 1} : 10

t = \frac{- ( - 19 ) - 1}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

t = 10, t = 9

24 x^{2} + 24 x - 18 = 0

(x + 5) (x + 7) + 1 = (2 x + 3)^{2}

(2 x - 5)^{2} - 1 = 0

5 y^{2} - 2 = 9 y

x^{2} + 6 x + 15 = 6

What are the solutions to the equation t^2-19t=-90 ?
The solutions to the equation t^2-19t=-90 are t=10,t=9
Find the zeros of t^2-19t=-90
The zeros of t^2-19t=-90 are t=10,t=9