What are the solutions to the equation -3x^2-x+6=0 ?

The solutions to the equation -3x^2-x+6=0 are x=-(1+sqrt(73))/6 ,x=(sqrt(73)-1)/6

Find the zeros of -3x^2-x+6=0

The zeros of -3x^2-x+6=0 are x=-(1+sqrt(73))/6 ,x=(sqrt(73)-1)/6

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- 3 x^{2} - x + 6 = 0

x = - \frac{1 + 73}{6}, x = \frac{73 - 1}{6}

Decimal Notation

x = - 1.59066 \dots, x = 1.25733 \dots

Solution steps

- 3 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

(- 1)^{2} - 4 (- 3) \cdot 6 = 73

x_{1, 2} = \frac{- ( - 1 ) \pm 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 73}{2 ( - 3 )}, x_{2} = \frac{- ( - 1 ) - 73}{2 ( - 3 )}

x = \frac{- ( - 1 ) + 73}{2 ( - 3 )} : - \frac{1 + 73}{6}

x = \frac{- ( - 1 ) - 73}{2 ( - 3 )} : \frac{73 - 1}{6}

The solutions to the quadratic equation are:

x = - \frac{1 + 73}{6}, x = \frac{73 - 1}{6}

x^{2} - 3 x + 25 = 0

2 x^{2} - 98 = 0

- 6 y^{2} + 4 y = - 3 y + 2

4 a^{2} - 63 = 4 a

- 4 x^{2} + 5 = - 59

What are the solutions to the equation -3x^2-x+6=0 ?
The solutions to the equation -3x^2-x+6=0 are x=-(1+sqrt(73))/6 ,x=(sqrt(73)-1)/6
Find the zeros of -3x^2-x+6=0
The zeros of -3x^2-x+6=0 are x=-(1+sqrt(73))/6 ,x=(sqrt(73)-1)/6