What are the solutions to the equation (a+1)3(a-1)=8 ?

The solutions to the equation (a+1)3(a-1)=8 are a=sqrt((3+8)/3),a=-sqrt((3+8)/3)

Find the zeros of (a+1)3(a-1)=8

The zeros of (a+1)3(a-1)=8 are a=sqrt((3+8)/3),a=-sqrt((3+8)/3)

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(a + 1) 3 (a - 1) = 8^{\circ}

a = \frac{3 + 8 ^{\circ}}{3}, a = - \frac{3 + 8 ^{\circ}}{3}

Decimal Notation

a = 1.02300 \dots, a = - 1.02300 \dots

Solution steps

(a + 1) \cdot 3 (a - 1) = 8^{\circ}

Expand

(a + 1) \cdot 3 (a - 1) : 3 a^{2} - 3

3 a^{2} - 3 = 8^{\circ}

Move

8^{\circ}

to the left side

3 a^{2} - 3 - 8^{\circ} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 3 ( - 3 - 8 ^{\circ} )}{2 \cdot 3}

0^{2} - 4 \cdot 3 (- 3 - 8^{\circ}) = 23 3 + 8^{\circ}

a_{1, 2} = \frac{- 0 \pm 2 3 3 + 8 ^{\circ}}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 0 + 2 3 3 + 8 ^{\circ}}{2 \cdot 3}, a_{2} = \frac{- 0 - 2 3 3 + 8 ^{\circ}}{2 \cdot 3}

a = \frac{- 0 + 2 3 3 + 8 ^{\circ}}{2 \cdot 3} : \frac{3 + 8 ^{\circ}}{3}

a = \frac{- 0 - 2 3 3 + 8 ^{\circ}}{2 \cdot 3} : - \frac{3 + 8 ^{\circ}}{3}

The solutions to the quadratic equation are:

a = \frac{3 + 8 ^{\circ}}{3}, a = - \frac{3 + 8 ^{\circ}}{3}

- 2 x^{2} + 8 x + 9 = 0

4 x^{2} - 14 x + 49 = 0

16 = \frac{4}{3} (8 x + 3) 34 (8 x + 3)

x^{2} = 3 (x + 6)

x^{2} + 4 x - 12 = 9

What are the solutions to the equation (a+1)3(a-1)=8 ?
The solutions to the equation (a+1)3(a-1)=8 are a=sqrt((3+8)/3),a=-sqrt((3+8)/3)
Find the zeros of (a+1)3(a-1)=8
The zeros of (a+1)3(a-1)=8 are a=sqrt((3+8)/3),a=-sqrt((3+8)/3)