What are the solutions to the equation quadraticformula x^2-10x+9=0 ?

The solutions to the equation quadraticformula x^2-10x+9=0 are x=9,x=1

Find the zeros of quadraticformula x^2-10x+9=0

The zeros of quadraticformula x^2-10x+9=0 are x=9,x=1

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x^{2} - 10 x + 9 = 0

x = 9, x = 1

Solution steps

x^{2} - 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

x = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

x = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 9, x = 1

(x + 3)^{2} = 3 x (5 x - 1) - 3 (x - 2)

(3 x - 8) (6 x - 1) = 3

2 a^{2} = x^{2}

0.2 (55 - x) = x^{2}

3 x^{2} - 4 x + 2 = 3

What are the solutions to the equation quadraticformula x^2-10x+9=0 ?
The solutions to the equation quadraticformula x^2-10x+9=0 are x=9,x=1
Find the zeros of quadraticformula x^2-10x+9=0
The zeros of quadraticformula x^2-10x+9=0 are x=9,x=1