What are the solutions to the equation -4x^2+5=0 ?

The solutions to the equation -4x^2+5=0 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

Find the zeros of -4x^2+5=0

The zeros of -4x^2+5=0 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 5 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.11803 \dots, x = - 1.11803 \dots

Solution steps

- 4 x^{2} + 5 = 0

Move

5

to the right side

- 4 x^{2} = - 5

Divide both sides by

- 4

x^{2} = \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{4}, x = - \frac{5}{4}

\frac{5}{4} = \frac{5}{2}

- \frac{5}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

x^{2} - 18 + 81 = 0

- 4 x^{2} + 13 = 0

x^{2} - 7 = 18

- 2 x^{2} + 1 x = - 3

3 x^{2} + x - 9 = 0

What are the solutions to the equation -4x^2+5=0 ?
The solutions to the equation -4x^2+5=0 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2
Find the zeros of -4x^2+5=0
The zeros of -4x^2+5=0 are x=(sqrt(5))/2 ,x=-(sqrt(5))/2