What are the solutions to the equation -4x^2+13=0 ?

The solutions to the equation -4x^2+13=0 are x=(sqrt(13))/2 ,x=-(sqrt(13))/2

Find the zeros of -4x^2+13=0

The zeros of -4x^2+13=0 are x=(sqrt(13))/2 ,x=-(sqrt(13))/2

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- 4 x^{2} + 13 = 0

x = \frac{13}{2}, x = - \frac{13}{2}

Decimal Notation

x = 1.80277 \dots, x = - 1.80277 \dots

Solution steps

- 4 x^{2} + 13 = 0

Move

13

to the right side

- 4 x^{2} = - 13

Divide both sides by

- 4

x^{2} = \frac{13}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{13}{4}, x = - \frac{13}{4}

\frac{13}{4} = \frac{13}{2}

- \frac{13}{4} = - \frac{13}{2}

x = \frac{13}{2}, x = - \frac{13}{2}

x^{2} - 7 = 18

- 2 x^{2} + 1 x = - 3

3 x^{2} + x - 9 = 0

- 5 x^{2} + 43 x - 56 = 0

- 2 x^{2} - x - 3 = 0

What are the solutions to the equation -4x^2+13=0 ?
The solutions to the equation -4x^2+13=0 are x=(sqrt(13))/2 ,x=-(sqrt(13))/2
Find the zeros of -4x^2+13=0
The zeros of -4x^2+13=0 are x=(sqrt(13))/2 ,x=-(sqrt(13))/2