What are the solutions to the equation -4x^2-24x-28=0 ?

The solutions to the equation -4x^2-24x-28=0 are x=-3-sqrt(2),x=-3+sqrt(2)

Find the zeros of -4x^2-24x-28=0

The zeros of -4x^2-24x-28=0 are x=-3-sqrt(2),x=-3+sqrt(2)

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- 4 x^{2} - 24 x - 28 = 0

x = - 3 - 2, x = - 3 + 2

Decimal Notation

x = - 4.41421 \dots, x = - 1.58578 \dots

Solution steps

- 4 x^{2} - 24 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 4 ) ( - 28 )}{2 ( - 4 )}

(- 24)^{2} - 4 (- 4) (- 28) = 82

x_{1, 2} = \frac{- ( - 24 ) \pm 8 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 2}{2 ( - 4 )}, x_{2} = \frac{- ( - 24 ) - 8 2}{2 ( - 4 )}

x = \frac{- ( - 24 ) + 8 2}{2 ( - 4 )} : - 3 - 2

x = \frac{- ( - 24 ) - 8 2}{2 ( - 4 )} : - 3 + 2

The solutions to the quadratic equation are:

x = - 3 - 2, x = - 3 + 2

12 x^{2} - 7 x - 1 = 0

(x) = 3 x^{2} - 6 x + 2

8 x^{2} + 2 x - 3 = 0

3 x^{2} + \frac{7}{5} = 2 x

36 + b^{2} = 100

What are the solutions to the equation -4x^2-24x-28=0 ?
The solutions to the equation -4x^2-24x-28=0 are x=-3-sqrt(2),x=-3+sqrt(2)
Find the zeros of -4x^2-24x-28=0
The zeros of -4x^2-24x-28=0 are x=-3-sqrt(2),x=-3+sqrt(2)