What are the solutions to the equation v^2=-32 ?

The solutions to the equation v^2=-32 are v=4sqrt(2)i,v=-4sqrt(2)i

Find the zeros of v^2=-32

The zeros of v^2=-32 are v=4sqrt(2)i,v=-4sqrt(2)i

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v^{2} = - 32

v = 42 i, v = - 42 i

Solution steps

v^{2} = - 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - 32, v = - - 32

- 32 = 42 i

- - 32 = - 42 i

v = 42 i, v = - 42 i

- x^{2} + 48 x - 575 = 0

76 = \frac{1}{2} (h (2 h + 3))

3 x (2 x + 2 x) = x (5 x - 5)

8 x^{2} - 6 b x - 3 b^{2} = 0

0 = - 2 x^{2} + 20 x + 48

What are the solutions to the equation v^2=-32 ?
The solutions to the equation v^2=-32 are v=4sqrt(2)i,v=-4sqrt(2)i
Find the zeros of v^2=-32
The zeros of v^2=-32 are v=4sqrt(2)i,v=-4sqrt(2)i