What are the solutions to the equation 10x^2+50x+60=0 ?

The solutions to the equation 10x^2+50x+60=0 are x=-2,x=-3

Find the zeros of 10x^2+50x+60=0

The zeros of 10x^2+50x+60=0 are x=-2,x=-3

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10 x^{2} + 50 x + 60 = 0

x = - 2, x = - 3

Solution steps

10 x^{2} + 50 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 10 \cdot 60}{2 \cdot 10}

5 0^{2} - 4 \cdot 10 \cdot 60 = 10

x_{1, 2} = \frac{- 50 \pm 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 50 + 10}{2 \cdot 10}, x_{2} = \frac{- 50 - 10}{2 \cdot 10}

x = \frac{- 50 + 10}{2 \cdot 10} : - 2

x = \frac{- 50 - 10}{2 \cdot 10} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

2 x^{2} - 5 b x - 3 b^{2} = 0

2 f (a) = 5 x^{2} - x + 2

n (n + 1) = 240

- 0.06 x^{2} + 4 x - 35 = 0

16 9^{2} = 12 5^{2} + x^{2}

What are the solutions to the equation 10x^2+50x+60=0 ?
The solutions to the equation 10x^2+50x+60=0 are x=-2,x=-3
Find the zeros of 10x^2+50x+60=0
The zeros of 10x^2+50x+60=0 are x=-2,x=-3