What are the solutions to the equation 2(x+1)^2=3 ?

The solutions to the equation 2(x+1)^2=3 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1

Find the zeros of 2(x+1)^2=3

The zeros of 2(x+1)^2=3 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x + 1)^{2} = 3

x = \frac{3}{2} - 1, x = - \frac{3}{2} - 1

Decimal Notation

x = 0.22474 \dots, x = - 2.22474 \dots

Solution steps

2 (x + 1)^{2} = 3

Divide both sides by

2

(x + 1)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = \frac{3}{2} : x = \frac{3}{2} - 1

Solve

x + 1 = - \frac{3}{2} : x = - \frac{3}{2} - 1

The solutions to the quadratic equation are:

x = \frac{3}{2} - 1, x = - \frac{3}{2} - 1

15 = 7 + 23 t - 16 t^{2}

x^{2} + 10 x - 8 = 0

y^{2} - 6 a y + (9 a^{2} - 4) = 0

(x - 7)^{2} = (3 x + 4) (x - 6) + 1

x, x^{2} - 81 = 0

What are the solutions to the equation 2(x+1)^2=3 ?
The solutions to the equation 2(x+1)^2=3 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1
Find the zeros of 2(x+1)^2=3
The zeros of 2(x+1)^2=3 are x=sqrt(3/2)-1,x=-sqrt(3/2)-1