What are the solutions to the equation 0.8x^2+0.8x-5=0 ?

The solutions to the equation 0.8x^2+0.8x-5=0 are x=(-1+sqrt(26))/2 ,x=-(1+sqrt(26))/2

Find the zeros of 0.8x^2+0.8x-5=0

The zeros of 0.8x^2+0.8x-5=0 are x=(-1+sqrt(26))/2 ,x=-(1+sqrt(26))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.8 x^{2} + 0.8 x - 5 = 0

x = \frac{- 1 + 26}{2}, x = - \frac{1 + 26}{2}

Decimal Notation

x = 2.04950 \dots, x = - 3.04950 \dots

Solution steps

0.8 x^{2} + 0.8 x - 5 = 0

Multiply both sides by

10

8 x^{2} + 8 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 ( - 50 )}{2 \cdot 8}

8^{2} - 4 \cdot 8 (- 50) = 826

x_{1, 2} = \frac{- 8 \pm 8 26}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 8 + 8 26}{2 \cdot 8}, x_{2} = \frac{- 8 - 8 26}{2 \cdot 8}

x = \frac{- 8 + 8 26}{2 \cdot 8} : \frac{- 1 + 26}{2}

x = \frac{- 8 - 8 26}{2 \cdot 8} : - \frac{1 + 26}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 26}{2}, x = - \frac{1 + 26}{2}

c^{2} + c - 7 = 0

x^{2} - 3 = x - 1

1 = (x - 1)^{2}

0.085 x^{2} - 5 x + 40 = 0

x^{2} - 8 x - 300 = 0

What are the solutions to the equation 0.8x^2+0.8x-5=0 ?
The solutions to the equation 0.8x^2+0.8x-5=0 are x=(-1+sqrt(26))/2 ,x=-(1+sqrt(26))/2
Find the zeros of 0.8x^2+0.8x-5=0
The zeros of 0.8x^2+0.8x-5=0 are x=(-1+sqrt(26))/2 ,x=-(1+sqrt(26))/2