What are the solutions to the equation -3x^2-2x=4-6x^2+1 ?

The solutions to the equation -3x^2-2x=4-6x^2+1 are x= 5/3 ,x=-1

Find the zeros of -3x^2-2x=4-6x^2+1

The zeros of -3x^2-2x=4-6x^2+1 are x= 5/3 ,x=-1

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- 3 x^{2} - 2 x = 4 - 6 x^{2} + 1

x = \frac{5}{3}, x = - 1

Decimal Notation

x = 1.66666 \dots, x = - 1

Solution steps

- 3 x^{2} - 2 x = 4 - 6 x^{2} + 1

Refine

- 3 x^{2} - 2 x = - 6 x^{2} + 5

Move

5

to the left side

- 3 x^{2} - 2 x - 5 = - 6 x^{2}

Move

6 x^{2}

to the left side

3 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 3}

x = \frac{- ( - 2 ) + 8}{2 \cdot 3} : \frac{5}{3}

x = \frac{- ( - 2 ) - 8}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 1

- 4 t^{2} - 20 t + 3 = 0

7 x^{2} - 8 x - 12 = 0

3 n^{2} - 20 n + 12 = 0

4 x^{2} + 9 + 12 x = 0

x^{2} + 4 x + 11 = 0

What are the solutions to the equation -3x^2-2x=4-6x^2+1 ?
The solutions to the equation -3x^2-2x=4-6x^2+1 are x= 5/3 ,x=-1
Find the zeros of -3x^2-2x=4-6x^2+1
The zeros of -3x^2-2x=4-6x^2+1 are x= 5/3 ,x=-1