What are the solutions to the equation 7x^2-8x-12=0 ?

The solutions to the equation 7x^2-8x-12=0 are x=2,x=-6/7

Find the zeros of 7x^2-8x-12=0

The zeros of 7x^2-8x-12=0 are x=2,x=-6/7

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7 x^{2} - 8 x - 12 = 0

x = 2, x = - \frac{6}{7}

Decimal Notation

x = 2, x = - 0.85714 \dots

Solution steps

7 x^{2} - 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 7 ( - 12 )}{2 \cdot 7}

(- 8)^{2} - 4 \cdot 7 (- 12) = 20

x_{1, 2} = \frac{- ( - 8 ) \pm 20}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 20}{2 \cdot 7}, x_{2} = \frac{- ( - 8 ) - 20}{2 \cdot 7}

x = \frac{- ( - 8 ) + 20}{2 \cdot 7} : 2

x = \frac{- ( - 8 ) - 20}{2 \cdot 7} : - \frac{6}{7}

The solutions to the quadratic equation are:

x = 2, x = - \frac{6}{7}

3 n^{2} - 20 n + 12 = 0

4 x^{2} + 9 + 12 x = 0

x^{2} + 4 x + 11 = 0

(17 x - 1)^{2} - 4 (17 x - 1) - 5 = 0

(x - 3)^{2} = 18

What are the solutions to the equation 7x^2-8x-12=0 ?
The solutions to the equation 7x^2-8x-12=0 are x=2,x=-6/7
Find the zeros of 7x^2-8x-12=0
The zeros of 7x^2-8x-12=0 are x=2,x=-6/7