What are the solutions to the equation 4v^2-9=-54 ?

The solutions to the equation 4v^2-9=-54 are v=(3sqrt(5))/2 i,v=-(3sqrt(5))/2 i

Find the zeros of 4v^2-9=-54

The zeros of 4v^2-9=-54 are v=(3sqrt(5))/2 i,v=-(3sqrt(5))/2 i

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4 v^{2} - 9 = - 54

v = \frac{3 5}{2} i, v = - \frac{3 5}{2} i

Solution steps

4 v^{2} - 9 = - 54

Move

9

to the right side

4 v^{2} = - 45

Divide both sides by

4

v^{2} = - \frac{45}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - \frac{45}{4}, v = - - \frac{45}{4}

- \frac{45}{4} = \frac{3 5}{2} i

- - \frac{45}{4} = - \frac{3 5}{2} i

v = \frac{3 5}{2} i, v = - \frac{3 5}{2} i

3 (x - 5) (x + 2) = 8

4.9 t^{2} - 5.2 t - 125 = 0

6 x^{2} + 8 x - 8 = 0

9 x^{2} - 30 x + 29 = 0

y, x^{2} - y^{2} = 0

What are the solutions to the equation 4v^2-9=-54 ?
The solutions to the equation 4v^2-9=-54 are v=(3sqrt(5))/2 i,v=-(3sqrt(5))/2 i
Find the zeros of 4v^2-9=-54
The zeros of 4v^2-9=-54 are v=(3sqrt(5))/2 i,v=-(3sqrt(5))/2 i