What are the solutions to the equation x^2-286x+20449=0 ?

The solutions to the equation x^2-286x+20449=0 are x=143

Find the zeros of x^2-286x+20449=0

The zeros of x^2-286x+20449=0 are x=143

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x^{2} - 286 x + 20449 = 0

x = 143

Solution steps

x^{2} - 286 x + 20449 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 286 ) \pm ( - 286 ) ^{2} - 4 \cdot 1 \cdot 20449}{2 \cdot 1}

(- 286)^{2} - 4 \cdot 1 \cdot 20449 = 0

x_{1, 2} = \frac{- ( - 286 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 286 )}{2 \cdot 1}

\frac{- ( - 286 )}{2 \cdot 1} = 143

x = 143

The solution to the quadratic equation is:

x = 143

x, x^{2} - 6 x + 7 = 0

y^{2} - 14 y + 46 = 0

55^{2} + x^{2} = 2 x^{2}

g (n) = n^{2} + 4 n, g (g (n))

x^{2} + 19 x - 42 = 0

What are the solutions to the equation x^2-286x+20449=0 ?
The solutions to the equation x^2-286x+20449=0 are x=143
Find the zeros of x^2-286x+20449=0
The zeros of x^2-286x+20449=0 are x=143