What are the solutions to the equation x^2+24x-11=0 ?

The solutions to the equation x^2+24x-11=0 are x=-12+sqrt(155),x=-12-sqrt(155)

Find the zeros of x^2+24x-11=0

The zeros of x^2+24x-11=0 are x=-12+sqrt(155),x=-12-sqrt(155)

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x^{2} + 24 x - 11 = 0

x = - 12 + 155, x = - 12 - 155

Decimal Notation

x = 0.44989 \dots, x = - 24.44989 \dots

Solution steps

x^{2} + 24 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot (- 11) = 2155

x_{1, 2} = \frac{- 24 \pm 2 155}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 2 155}{2 \cdot 1}, x_{2} = \frac{- 24 - 2 155}{2 \cdot 1}

x = \frac{- 24 + 2 155}{2 \cdot 1} : - 12 + 155

x = \frac{- 24 - 2 155}{2 \cdot 1} : - 12 - 155

The solutions to the quadratic equation are:

x = - 12 + 155, x = - 12 - 155

2 x^{2} + 12 x - 5

10 x^{2} + 28 x - 8 = 0

π x^{2} - \frac{1}{5} x + 19 = 0

x^{2} + 6 x^{2} + 9 x = 0

(n + 3)^{2} + 2 n = 8 n + 13

What are the solutions to the equation x^2+24x-11=0 ?
The solutions to the equation x^2+24x-11=0 are x=-12+sqrt(155),x=-12-sqrt(155)
Find the zeros of x^2+24x-11=0
The zeros of x^2+24x-11=0 are x=-12+sqrt(155),x=-12-sqrt(155)