What are the solutions to the equation (n+3)^2+2n=8n+13 ?

The solutions to the equation (n+3)^2+2n=8n+13 are n=2,n=-2

Find the zeros of (n+3)^2+2n=8n+13

The zeros of (n+3)^2+2n=8n+13 are n=2,n=-2

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(n + 3)^{2} + 2 n = 8 n + 13

n = 2, n = - 2

Solution steps

(n + 3)^{2} + 2 n = 8 n + 13

Expand

(n + 3)^{2} + 2 n : n^{2} + 8 n + 9

n^{2} + 8 n + 9 = 8 n + 13

Move

9

to the right side

n^{2} + 8 n = 8 n + 4

Move

8 n

to the left side

n^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 4, n = - 4

4 = 2

- 4 = - 2

n = 2, n = - 2

(x + 1)^{2} - 14 (x + 1) + 45 = 0

4 x^{2} - 12 x - 72 = 0

x^{2} + 5 x + 1 = 0

5 x^{2} + 0.7 x - 2.6 = 0

12 x^{2} + 4 x - 21 = 0

What are the solutions to the equation (n+3)^2+2n=8n+13 ?
The solutions to the equation (n+3)^2+2n=8n+13 are n=2,n=-2
Find the zeros of (n+3)^2+2n=8n+13
The zeros of (n+3)^2+2n=8n+13 are n=2,n=-2