What are the solutions to the equation 5x^2+0.7x-2.6=0 ?

The solutions to the equation 5x^2+0.7x-2.6=0 are x=(-7+sqrt(5249))/(100),x=(-7-sqrt(5249))/(100)

Find the zeros of 5x^2+0.7x-2.6=0

The zeros of 5x^2+0.7x-2.6=0 are x=(-7+sqrt(5249))/(100),x=(-7-sqrt(5249))/(100)

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5 x^{2} + 0.7 x - 2.6 = 0

x = \frac{- 7 + 5249}{100}, x = \frac{- 7 - 5249}{100}

Decimal Notation

x = 0.65449 \dots, x = - 0.79449 \dots

Solution steps

5 x^{2} + 0.7 x - 2.6 = 0

Multiply both sides by

10

50 x^{2} + 7 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 50 ( - 26 )}{2 \cdot 50}

7^{2} - 4 \cdot 50 (- 26) = 5249

x_{1, 2} = \frac{- 7 \pm 5249}{2 \cdot 50}

Separate the solutions

x_{1} = \frac{- 7 + 5249}{2 \cdot 50}, x_{2} = \frac{- 7 - 5249}{2 \cdot 50}

x = \frac{- 7 + 5249}{2 \cdot 50} : \frac{- 7 + 5249}{100}

x = \frac{- 7 - 5249}{2 \cdot 50} : \frac{- 7 - 5249}{100}

The solutions to the quadratic equation are:

x = \frac{- 7 + 5249}{100}, x = \frac{- 7 - 5249}{100}

12 x^{2} + 4 x - 21 = 0

(w + 1)^{2} - 36 = 0

8 = a^{2}

(k + 4)^{2} - 169 = 0

(x) (x - 7) = 120

What are the solutions to the equation 5x^2+0.7x-2.6=0 ?
The solutions to the equation 5x^2+0.7x-2.6=0 are x=(-7+sqrt(5249))/(100),x=(-7-sqrt(5249))/(100)
Find the zeros of 5x^2+0.7x-2.6=0
The zeros of 5x^2+0.7x-2.6=0 are x=(-7+sqrt(5249))/(100),x=(-7-sqrt(5249))/(100)