What are the solutions to the equation (k+4)^2-169=0 ?

The solutions to the equation (k+4)^2-169=0 are k=9,k=-17

Find the zeros of (k+4)^2-169=0

The zeros of (k+4)^2-169=0 are k=9,k=-17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(k + 4)^{2} - 169 = 0

k = 9, k = - 17

Solution steps

(k + 4)^{2} - 169 = 0

Move

169

to the right side

(k + 4)^{2} = 169

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 4 = 169 : k = 9

Solve

k + 4 = - 169 : k = - 17

The solutions to the quadratic equation are:

k = 9, k = - 17

(x) (x - 7) = 120

x, f (x + 3) = 4 x^{2} + 2 x - 3

x^{2} - x - 4

(x - 4)^{2} - 3 = 6

(w + 1)^{2} - 32 = 0

What are the solutions to the equation (k+4)^2-169=0 ?
The solutions to the equation (k+4)^2-169=0 are k=9,k=-17
Find the zeros of (k+4)^2-169=0
The zeros of (k+4)^2-169=0 are k=9,k=-17