What are the solutions to the equation (x-4)^2-3=6 ?

The solutions to the equation (x-4)^2-3=6 are x=7,x=1

Find the zeros of (x-4)^2-3=6

The zeros of (x-4)^2-3=6 are x=7,x=1

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(x - 4)^{2} - 3 = 6

x = 7, x = 1

Solution steps

(x - 4)^{2} - 3 = 6

Move

3

to the right side

(x - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 9 : x = 7

Solve

x - 4 = - 9 : x = 1

The solutions to the quadratic equation are:

x = 7, x = 1

(w + 1)^{2} - 32 = 0

(x - 4)^{2} - 2 = 0

b^{2} = 0

a x^{2} - 2 x + 4 = 0

x, f = x^{2} - k x + k^{2}

What are the solutions to the equation (x-4)^2-3=6 ?
The solutions to the equation (x-4)^2-3=6 are x=7,x=1
Find the zeros of (x-4)^2-3=6
The zeros of (x-4)^2-3=6 are x=7,x=1