What are the solutions to the equation x(x-3)+4x+2=5x+2 ?

The solutions to the equation x(x-3)+4x+2=5x+2 are x=4,x=0

Find the zeros of x(x-3)+4x+2=5x+2

The zeros of x(x-3)+4x+2=5x+2 are x=4,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (x - 3) + 4 x + 2 = 5 x + 2

x = 4, x = 0

Solution steps

x (x - 3) + 4 x + 2 = 5 x + 2

Expand

x (x - 3) + 4 x + 2 : x^{2} + x + 2

x^{2} + x + 2 = 5 x + 2

Move

2

to the left side

x^{2} + x = 5 x

Move

5 x

to the left side

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x, f = 2 x^{2} - 3 f (x + 2)

6 t^{2} - 89 t + 12 = 0

0 = (x - 2) (x - 6)

18 = 6 X + X (X - 13)

m^{2} - 3 m = 70

What are the solutions to the equation x(x-3)+4x+2=5x+2 ?
The solutions to the equation x(x-3)+4x+2=5x+2 are x=4,x=0
Find the zeros of x(x-3)+4x+2=5x+2
The zeros of x(x-3)+4x+2=5x+2 are x=4,x=0