What are the solutions to the equation 18=6X+X(X-13) ?

The solutions to the equation 18=6X+X(X-13) are X=9,X=-2

Find the zeros of 18=6X+X(X-13)

The zeros of 18=6X+X(X-13) are X=9,X=-2

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18 = 6 X + X (X - 13)

X = 9, X = - 2

Solution steps

18 = 6 X + X (X - 13)

Expand

6 X + X (X - 13) : X^{2} - 7 X

18 = X^{2} - 7 X

Switch sides

X^{2} - 7 X = 18

Move

18

to the left side

X^{2} - 7 X - 18 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

X_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, X_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

X = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

X = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

X = 9, X = - 2

m^{2} - 3 m = 70

(5 x) (x + 3) = 0

3 x^{2} = - 10 x + 8

2 x^{2} + 3 x = 5

3 x^{2} + 2 x - 11 = 0

What are the solutions to the equation 18=6X+X(X-13) ?
The solutions to the equation 18=6X+X(X-13) are X=9,X=-2
Find the zeros of 18=6X+X(X-13)
The zeros of 18=6X+X(X-13) are X=9,X=-2