What are the solutions to the equation 4m^2-3m-6=0 ?

The solutions to the equation 4m^2-3m-6=0 are m=(3+sqrt(105))/8 ,m=(3-sqrt(105))/8

Find the zeros of 4m^2-3m-6=0

The zeros of 4m^2-3m-6=0 are m=(3+sqrt(105))/8 ,m=(3-sqrt(105))/8

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4 m^{2} - 3 m - 6 = 0

m = \frac{3 + 105}{8}, m = \frac{3 - 105}{8}

Decimal Notation

m = 1.65586 \dots, m = - 0.90586 \dots

Solution steps

4 m^{2} - 3 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 6) = 105

m_{1, 2} = \frac{- ( - 3 ) \pm 105}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 105}{2 \cdot 4}, m_{2} = \frac{- ( - 3 ) - 105}{2 \cdot 4}

m = \frac{- ( - 3 ) + 105}{2 \cdot 4} : \frac{3 + 105}{8}

m = \frac{- ( - 3 ) - 105}{2 \cdot 4} : \frac{3 - 105}{8}

The solutions to the quadratic equation are:

m = \frac{3 + 105}{8}, m = \frac{3 - 105}{8}

(2 x - 1) (x + 3) = x + 1

x^{2} + 11 x + 20 = 0

2 a^{2} + 2 a - 60 = 0

(3 X - 1)^{2} + X (X - 3) = - 1

x^{2} - 10 x = x + 12

What are the solutions to the equation 4m^2-3m-6=0 ?
The solutions to the equation 4m^2-3m-6=0 are m=(3+sqrt(105))/8 ,m=(3-sqrt(105))/8
Find the zeros of 4m^2-3m-6=0
The zeros of 4m^2-3m-6=0 are m=(3+sqrt(105))/8 ,m=(3-sqrt(105))/8