What are the solutions to the equation solvefor x,y=-x^2+6x-8 ?

The solutions to the equation solvefor x,y=-x^2+6x-8 are x=3-sqrt(-y+1),x=sqrt(-y+1)+3

Find the zeros of solvefor x,y=-x^2+6x-8

The zeros of solvefor x,y=-x^2+6x-8 are x=3-sqrt(-y+1),x=sqrt(-y+1)+3

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solve for

x, y = - x^{2} + 6 x - 8

x = 3 - - y + 1, x = - y + 1 + 3

Solution steps

y = - x^{2} + 6 x - 8

Switch sides

- x^{2} + 6 x - 8 = y

Move

y

to the left side

- x^{2} + 6 x - 8 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 8 - y )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 8 - y) : 2 - y + 1

x_{1, 2} = \frac{- 6 \pm 2 - y + 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 - y + 1}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 - y + 1}{2 ( - 1 )}

x = \frac{- 6 + 2 - y + 1}{2 ( - 1 )} : 3 - - y + 1

x = \frac{- 6 - 2 - y + 1}{2 ( - 1 )} : - y + 1 + 3

The solutions to the quadratic equation are:

x = 3 - - y + 1, x = - y + 1 + 3

k^{2} - 10 k + 9 = 0

2 (x + 1)^{2} = 5 - 2 x (11 x + 5)

3 x^{2} - 5 x + 2 = 0, 4 x^{2} + 3 x - 22 = 0

6 x^{2} + 7 x - 3 = 0

x^{2} + 339 = 0

What are the solutions to the equation solvefor x,y=-x^2+6x-8 ?
The solutions to the equation solvefor x,y=-x^2+6x-8 are x=3-sqrt(-y+1),x=sqrt(-y+1)+3
Find the zeros of solvefor x,y=-x^2+6x-8
The zeros of solvefor x,y=-x^2+6x-8 are x=3-sqrt(-y+1),x=sqrt(-y+1)+3