What are the solutions to the equation 3x^2-5x+2=0,4x^2+3x-22=0 ?

The solutions to the equation 3x^2-5x+2=0,4x^2+3x-22=0 are x=1,x= 2/3

Find the zeros of 3x^2-5x+2=0,4x^2+3x-22=0

The zeros of 3x^2-5x+2=0,4x^2+3x-22=0 are x=1,x= 2/3

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3 x^{2} - 5 x + 2 = 0, 4 x^{2} + 3 x - 22 = 0

x = 1, x = \frac{2}{3}

Decimal Notation

x = 1, x = 0.66666 \dots

Solution steps

3 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 3}

x = \frac{- ( - 5 ) + 1}{2 \cdot 3} : 1

x = \frac{- ( - 5 ) - 1}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = \frac{2}{3}

6 x^{2} + 7 x - 3 = 0

x^{2} + 339 = 0

0 = 3 x^{2} + 17 x - 160

y^{2} - 15 y - 16 = 0

6 x^{2} - x - 5 = 0

What are the solutions to the equation 3x^2-5x+2=0,4x^2+3x-22=0 ?
The solutions to the equation 3x^2-5x+2=0,4x^2+3x-22=0 are x=1,x= 2/3
Find the zeros of 3x^2-5x+2=0,4x^2+3x-22=0
The zeros of 3x^2-5x+2=0,4x^2+3x-22=0 are x=1,x= 2/3