What are the solutions to the equation 0=3x^2+17x-160 ?

The solutions to the equation 0=3x^2+17x-160 are x=5,x=-32/3

Find the zeros of 0=3x^2+17x-160

The zeros of 0=3x^2+17x-160 are x=5,x=-32/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 3 x^{2} + 17 x - 160

x = 5, x = - \frac{32}{3}

Decimal Notation

x = 5, x = - 10.66666 \dots

Solution steps

0 = 3 x^{2} + 17 x - 160

Switch sides

3 x^{2} + 17 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 ( - 160 )}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 (- 160) = 47

x_{1, 2} = \frac{- 17 \pm 47}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 47}{2 \cdot 3}, x_{2} = \frac{- 17 - 47}{2 \cdot 3}

x = \frac{- 17 + 47}{2 \cdot 3} : 5

x = \frac{- 17 - 47}{2 \cdot 3} : - \frac{32}{3}

The solutions to the quadratic equation are:

x = 5, x = - \frac{32}{3}

y^{2} - 15 y - 16 = 0

6 x^{2} - x - 5 = 0

(y - 2)^{2} = 16

(z - 2)^{2} - 30 = 6

3 p^{2} - p + 5 = 0

What are the solutions to the equation 0=3x^2+17x-160 ?
The solutions to the equation 0=3x^2+17x-160 are x=5,x=-32/3
Find the zeros of 0=3x^2+17x-160
The zeros of 0=3x^2+17x-160 are x=5,x=-32/3