What are the solutions to the equation (1-3(1))x^2+3x-4=0 ?

The solutions to the equation (1-3(1))x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4

Find the zeros of (1-3(1))x^2+3x-4=0

The zeros of (1-3(1))x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - 3 (1)) x^{2} + 3 x - 4 = 0

x = \frac{3}{4} - i \frac{23}{4}, x = \frac{3}{4} + i \frac{23}{4}

Solution steps

(1 - 3 (1)) x^{2} + 3 x - 4 = 0

Expand

(1 - 3 (1)) x^{2} + 3 x - 4 : - 2 x^{2} + 3 x - 4

- 2 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

3^{2} - 4 (- 2) (- 4) : 23 i

x_{1, 2} = \frac{- 3 \pm 23 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 23 i}{2 ( - 2 )}, x_{2} = \frac{- 3 - 23 i}{2 ( - 2 )}

x = \frac{- 3 + 23 i}{2 ( - 2 )} : \frac{3}{4} - i \frac{23}{4}

x = \frac{- 3 - 23 i}{2 ( - 2 )} : \frac{3}{4} + i \frac{23}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{23}{4}, x = \frac{3}{4} + i \frac{23}{4}

x^{2} - 5 a x - 36 a^{2} = 0

3 x^{2} = 16 - 2 x

0 = - x^{2} + 3

n^{2} + \frac{n}{3} = - 180

2 x^{2} - 6 x + 2

What are the solutions to the equation (1-3(1))x^2+3x-4=0 ?
The solutions to the equation (1-3(1))x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4
Find the zeros of (1-3(1))x^2+3x-4=0
The zeros of (1-3(1))x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4