What are the solutions to the equation x^2+3cx+6=0 ?

The solutions to the equation x^2+3cx+6=0 are x=(-3c+sqrt(9c^2-24))/2 ,x=(-3c-sqrt(9c^2-24))/2

Find the zeros of x^2+3cx+6=0

The zeros of x^2+3cx+6=0 are x=(-3c+sqrt(9c^2-24))/2 ,x=(-3c-sqrt(9c^2-24))/2

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x^{2} + 3 c x + 6 = 0

x = \frac{- 3 c + 9 c ^{2} - 24}{2}, x = \frac{- 3 c - 9 c ^{2} - 24}{2}

Solution steps

x^{2} + 3 c x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 c \pm ( 3 c ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(3 c)^{2} - 4 \cdot 1 \cdot 6 : 9 c^{2} - 24

x_{1, 2} = \frac{- 3 c \pm 9 c ^{2} - 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 c + 9 c ^{2} - 24}{2 \cdot 1}, x_{2} = \frac{- 3 c - 9 c ^{2} - 24}{2 \cdot 1}

x = \frac{- 3 c + 9 c ^{2} - 24}{2 \cdot 1} : \frac{- 3 c + 9 c ^{2} - 24}{2}

x = \frac{- 3 c - 9 c ^{2} - 24}{2 \cdot 1} : \frac{- 3 c - 9 c ^{2} - 24}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 c + 9 c ^{2} - 24}{2}, x = \frac{- 3 c - 9 c ^{2} - 24}{2}

13 x^{2} - 58 x + 104 = 0

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x^{2} + 20 x + 2500 = 0

What are the solutions to the equation x^2+3cx+6=0 ?
The solutions to the equation x^2+3cx+6=0 are x=(-3c+sqrt(9c^2-24))/2 ,x=(-3c-sqrt(9c^2-24))/2
Find the zeros of x^2+3cx+6=0
The zeros of x^2+3cx+6=0 are x=(-3c+sqrt(9c^2-24))/2 ,x=(-3c-sqrt(9c^2-24))/2