What are the solutions to the equation 40x^2-44x-27=0 ?

The solutions to the equation 40x^2-44x-27=0 are x=(11+sqrt(391))/(20),x=(11-sqrt(391))/(20)

Find the zeros of 40x^2-44x-27=0

The zeros of 40x^2-44x-27=0 are x=(11+sqrt(391))/(20),x=(11-sqrt(391))/(20)

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40 x^{2} - 44 x - 27 = 0

x = \frac{11 + 391}{20}, x = \frac{11 - 391}{20}

Decimal Notation

x = 1.53868 \dots, x = - 0.43868 \dots

Solution steps

40 x^{2} - 44 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 44 ) \pm ( - 44 ) ^{2} - 4 \cdot 40 ( - 27 )}{2 \cdot 40}

(- 44)^{2} - 4 \cdot 40 (- 27) = 4391

x_{1, 2} = \frac{- ( - 44 ) \pm 4 391}{2 \cdot 40}

Separate the solutions

x_{1} = \frac{- ( - 44 ) + 4 391}{2 \cdot 40}, x_{2} = \frac{- ( - 44 ) - 4 391}{2 \cdot 40}

x = \frac{- ( - 44 ) + 4 391}{2 \cdot 40} : \frac{11 + 391}{20}

x = \frac{- ( - 44 ) - 4 391}{2 \cdot 40} : \frac{11 - 391}{20}

The solutions to the quadratic equation are:

x = \frac{11 + 391}{20}, x = \frac{11 - 391}{20}

(- 4 x - 5) (- x + 5) = 0

8^{2} + 1 4^{2} = x^{2}

x^{2} + 20 x + 2500 = 0

- 5 x^{2} = - 8

0 = 2 x^{2} - 7 x - 4

What are the solutions to the equation 40x^2-44x-27=0 ?
The solutions to the equation 40x^2-44x-27=0 are x=(11+sqrt(391))/(20),x=(11-sqrt(391))/(20)
Find the zeros of 40x^2-44x-27=0
The zeros of 40x^2-44x-27=0 are x=(11+sqrt(391))/(20),x=(11-sqrt(391))/(20)