What are the solutions to the equation 10-5(x-4)^2=10 ?

The solutions to the equation 10-5(x-4)^2=10 are x=4

Find the zeros of 10-5(x-4)^2=10

The zeros of 10-5(x-4)^2=10 are x=4

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10 - 5 (x - 4)^{2} = 10

x = 4

Solution steps

10 - 5 (x - 4)^{2} = 10

Move

10

to the right side

- 5 (x - 4)^{2} = 0

Divide both sides by

- 5

(x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 4 = 0 : x = 4

The solution to the quadratic equation is:

x = 4

n^{2} = 45

0.5 (1.2 - x)^{2} = 8 x^{2}

a^{2} + 6^{2} = 1 1^{2}

m^{2} + 128 = 0

4 x^{2} = - x + 4

What are the solutions to the equation 10-5(x-4)^2=10 ?
The solutions to the equation 10-5(x-4)^2=10 are x=4
Find the zeros of 10-5(x-4)^2=10
The zeros of 10-5(x-4)^2=10 are x=4