What are the solutions to the equation m^2+128=0 ?

The solutions to the equation m^2+128=0 are m=8sqrt(2)i,m=-8sqrt(2)i

Find the zeros of m^2+128=0

The zeros of m^2+128=0 are m=8sqrt(2)i,m=-8sqrt(2)i

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m^{2} + 128 = 0

m = 82 i, m = - 82 i

Solution steps

m^{2} + 128 = 0

Move

128

to the right side

m^{2} = - 128

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 128, m = - - 128

- 128 = 82 i

- - 128 = - 82 i

m = 82 i, m = - 82 i

4 x^{2} = - x + 4

- 2 x^{2} - 10 x + 12 = 0

\frac{1}{2} x + 1 = x^{2} - 2 x + 1

v, F = \frac{h M v ^{2}}{r}

x (x + 1)^{2} = (x - 1)^{3}

What are the solutions to the equation m^2+128=0 ?
The solutions to the equation m^2+128=0 are m=8sqrt(2)i,m=-8sqrt(2)i
Find the zeros of m^2+128=0
The zeros of m^2+128=0 are m=8sqrt(2)i,m=-8sqrt(2)i