What are the solutions to the equation completesquare 2x^2-8x+1=0 ?

The solutions to the equation completesquare 2x^2-8x+1=0 are x=sqrt(7/2)+2,x=-sqrt(7/2)+2

Find the zeros of completesquare 2x^2-8x+1=0

The zeros of completesquare 2x^2-8x+1=0 are x=sqrt(7/2)+2,x=-sqrt(7/2)+2

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2 x^{2} - 8 x + 1 = 0

x = \frac{7}{2} + 2, x = - \frac{7}{2} + 2

Decimal Notation

x = 3.87082 \dots, x = 0.12917 \dots

Solution steps

2 x^{2} - 8 x + 1 = 0

Move

1

to the right side

2 x^{2} - 8 x = - 1

Divide both sides by

2

\frac{2 x ^{2} - 8 x}{2} = \frac{- 1}{2}

x^{2} - 4 x = - \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = \frac{7}{2}

For

the solutions are

f (x) = a, - a

Solve

x - 2 = \frac{7}{2} : x = \frac{7}{2} + 2

Solve

x - 2 = - \frac{7}{2} : x = - \frac{7}{2} + 2

The solutions to the quadratic equation are:

x = \frac{7}{2} + 2, x = - \frac{7}{2} + 2

- 2 y^{2} = 9

46 x + 7 x^{2} = 21

3.14 \cdot x^{2} = 4

2 x^{2} + 28 x + 1

x, f (x - 2) = x^{2} + 8 x + 5

What are the solutions to the equation completesquare 2x^2-8x+1=0 ?
The solutions to the equation completesquare 2x^2-8x+1=0 are x=sqrt(7/2)+2,x=-sqrt(7/2)+2
Find the zeros of completesquare 2x^2-8x+1=0
The zeros of completesquare 2x^2-8x+1=0 are x=sqrt(7/2)+2,x=-sqrt(7/2)+2