What are the solutions to the equation 10-5x=2x^2 ?

The solutions to the equation 10-5x=2x^2 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4

Find the zeros of 10-5x=2x^2

The zeros of 10-5x=2x^2 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4

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10 - 5 x = 2 x^{2}

x = \frac{- 5 + 105}{4}, x = \frac{- 5 - 105}{4}

Decimal

x = 1.31173 \dots, x = - 3.81173 \dots

Solution steps

10 - 5 x = 2 x^{2}

Switch sides

2 x^{2} = 10 - 5 x

Move

5 x

to the left side

2 x^{2} + 5 x = 10

Move

10

to the left side

2 x^{2} + 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 10) = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 105}{2 \cdot 2}, x_{2} = \frac{- 5 - 105}{2 \cdot 2}

x = \frac{- 5 + 105}{2 \cdot 2} : \frac{- 5 + 105}{4}

x = \frac{- 5 - 105}{2 \cdot 2} : \frac{- 5 - 105}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 105}{4}, x = \frac{- 5 - 105}{4}

(y - 6)^{2} - 4 = 14

3 x^{2} - 27 = 0

(2 x + 3)^{2} = 6

u^{2} + u - 30 = 0

2 x^{2} - 9 x = - 7

What are the solutions to the equation 10-5x=2x^2 ?
The solutions to the equation 10-5x=2x^2 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4
Find the zeros of 10-5x=2x^2
The zeros of 10-5x=2x^2 are x=(-5+sqrt(105))/4 ,x=(-5-sqrt(105))/4