What are the solutions to the equation 3b^2+9b-9=0 ?

The solutions to the equation 3b^2+9b-9=0 are b=(-3+sqrt(21))/2 ,b=-(3+sqrt(21))/2

Find the zeros of 3b^2+9b-9=0

The zeros of 3b^2+9b-9=0 are b=(-3+sqrt(21))/2 ,b=-(3+sqrt(21))/2

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3 b^{2} + 9 b - 9 = 0

b = \frac{- 3 + 21}{2}, b = - \frac{3 + 21}{2}

Decimal Notation

b = 0.79128 \dots, b = - 3.79128 \dots

Solution steps

3 b^{2} + 9 b - 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 9) = 321

b_{1, 2} = \frac{- 9 \pm 3 21}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 9 + 3 21}{2 \cdot 3}, b_{2} = \frac{- 9 - 3 21}{2 \cdot 3}

b = \frac{- 9 + 3 21}{2 \cdot 3} : \frac{- 3 + 21}{2}

b = \frac{- 9 - 3 21}{2 \cdot 3} : - \frac{3 + 21}{2}

The solutions to the quadratic equation are:

b = \frac{- 3 + 21}{2}, b = - \frac{3 + 21}{2}

21 - 20 x - x^{2} = 0

5 x^{2} - 16 x - 16 = 0

x, y^{2} + x^{2} = z^{2}

(y + 7) (y - 3) = 0

x c (x + 2) - 5 = b (x - 3)

What are the solutions to the equation 3b^2+9b-9=0 ?
The solutions to the equation 3b^2+9b-9=0 are b=(-3+sqrt(21))/2 ,b=-(3+sqrt(21))/2
Find the zeros of 3b^2+9b-9=0
The zeros of 3b^2+9b-9=0 are b=(-3+sqrt(21))/2 ,b=-(3+sqrt(21))/2