What are the solutions to the equation (y+7)(y-3)=0 ?

The solutions to the equation (y+7)(y-3)=0 are y=-7,y=3

Find the zeros of (y+7)(y-3)=0

The zeros of (y+7)(y-3)=0 are y=-7,y=3

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(y + 7) (y - 3) = 0

y = - 7, y = 3

Solution steps

(y + 7) (y - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 7 = 0 or y - 3 = 0

Solve

y + 7 = 0 : y = - 7

Solve

y - 3 = 0 : y = 3

The solutions to the quadratic equation are:

y = - 7, y = 3

x c (x + 2) - 5 = b (x - 3)

0 = - 2 x^{2} + 4 x

u^{2} - 18 u

9 - y^{2} = 0

(x - 2)^{2} + 4 (x - 2) = 0

What are the solutions to the equation (y+7)(y-3)=0 ?
The solutions to the equation (y+7)(y-3)=0 are y=-7,y=3
Find the zeros of (y+7)(y-3)=0
The zeros of (y+7)(y-3)=0 are y=-7,y=3