What are the solutions to the equation (x-2)^2+4(x-2)=0 ?

The solutions to the equation (x-2)^2+4(x-2)=0 are x=2,x=-2

Find the zeros of (x-2)^2+4(x-2)=0

The zeros of (x-2)^2+4(x-2)=0 are x=2,x=-2

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(x - 2)^{2} + 4 (x - 2) = 0

x = 2, x = - 2

Solution steps

(x - 2)^{2} + 4 (x - 2) = 0

Expand

(x - 2)^{2} + 4 (x - 2) : x^{2} - 4

x^{2} - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 4) = 4

x_{1, 2} = \frac{- 0 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 4}{2 \cdot 1}, x_{2} = \frac{- 0 - 4}{2 \cdot 1}

x = \frac{- 0 + 4}{2 \cdot 1} : 2

x = \frac{- 0 - 4}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

2 x^{2} + x - 15 = 0

3 (x - 6)^{2} + 4 = 0

lo g_{3} (81) = x^{2}

3 n^{2} - 4 n + 9 = 3

5 (x - 3)^{2} = 20

What are the solutions to the equation (x-2)^2+4(x-2)=0 ?
The solutions to the equation (x-2)^2+4(x-2)=0 are x=2,x=-2
Find the zeros of (x-2)^2+4(x-2)=0
The zeros of (x-2)^2+4(x-2)=0 are x=2,x=-2