What are the solutions to the equation (x-5)^2-8=-26 ?

The solutions to the equation (x-5)^2-8=-26 are x=3sqrt(2)i+5,x=-3sqrt(2)i+5

Find the zeros of (x-5)^2-8=-26

The zeros of (x-5)^2-8=-26 are x=3sqrt(2)i+5,x=-3sqrt(2)i+5

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(x - 5)^{2} - 8 = - 26

x = 32 i + 5, x = - 32 i + 5

Solution steps

(x - 5)^{2} - 8 = - 26

Move

8

to the right side

(x - 5)^{2} = - 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 18 : x = 32 i + 5

Solve

x - 5 = - - 18 : x = - 32 i + 5

The solutions to the quadratic equation are:

x = 32 i + 5, x = - 32 i + 5

p^{2} + 2 p - 1 = 0

5 w^{2} - 9 w = 2

2 x^{2} - x 5 - 15 = 0

80 x + \frac{1}{2} (4) x^{2} - 1000 = 0

2 b^{2} = 10

What are the solutions to the equation (x-5)^2-8=-26 ?
The solutions to the equation (x-5)^2-8=-26 are x=3sqrt(2)i+5,x=-3sqrt(2)i+5
Find the zeros of (x-5)^2-8=-26
The zeros of (x-5)^2-8=-26 are x=3sqrt(2)i+5,x=-3sqrt(2)i+5