What are the solutions to the equation 2x^2-xsqrt(5)-15=0 ?

The solutions to the equation 2x^2-xsqrt(5)-15=0 are x=(3sqrt(5))/2 ,x=-sqrt(5)

Find the zeros of 2x^2-xsqrt(5)-15=0

The zeros of 2x^2-xsqrt(5)-15=0 are x=(3sqrt(5))/2 ,x=-sqrt(5)

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2 x^{2} - x 5 - 15 = 0

x = \frac{3 5}{2}, x = - 5

Decimal Notation

x = 3.35410 \dots, x = - 2.23606 \dots

Solution steps

2 x^{2} - x 5 - 15 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 15) = 55

x_{1, 2} = \frac{- ( - 5 ) \pm 5 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5 5}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 5 5}{2 \cdot 2}

x = \frac{- ( - 5 ) + 5 5}{2 \cdot 2} : \frac{3 5}{2}

x = \frac{- ( - 5 ) - 5 5}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{3 5}{2}, x = - 5

80 x + \frac{1}{2} (4) x^{2} - 1000 = 0

2 b^{2} = 10

4 x^{2} + 2 x + 4 = 2 x + 8

y^{2} - 225 = 0

(z + 9)^{2} = - 9

What are the solutions to the equation 2x^2-xsqrt(5)-15=0 ?
The solutions to the equation 2x^2-xsqrt(5)-15=0 are x=(3sqrt(5))/2 ,x=-sqrt(5)
Find the zeros of 2x^2-xsqrt(5)-15=0
The zeros of 2x^2-xsqrt(5)-15=0 are x=(3sqrt(5))/2 ,x=-sqrt(5)