What are the solutions to the equation (z+9)^2=-9 ?

The solutions to the equation (z+9)^2=-9 are z=3i-9,z=-3i-9

Find the zeros of (z+9)^2=-9

The zeros of (z+9)^2=-9 are z=3i-9,z=-3i-9

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(z + 9)^{2} = - 9

z = 3 i - 9, z = - 3 i - 9

Solution steps

(z + 9)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 9 = - 9 : z = 3 i - 9

Solve

z + 9 = - - 9 : z = - 3 i - 9

The solutions to the quadratic equation are:

z = 3 i - 9, z = - 3 i - 9

2 x^{2} - 0.41 x - 1.27 = 0

x, 4 x^{2} (36 - k^{2}) = 0

\frac{4}{6} = x^{2}

(u)^{2} + u \cdot 2^{2} = 3

4 u^{2} - 7 u - 2 = 0

What are the solutions to the equation (z+9)^2=-9 ?
The solutions to the equation (z+9)^2=-9 are z=3i-9,z=-3i-9
Find the zeros of (z+9)^2=-9
The zeros of (z+9)^2=-9 are z=3i-9,z=-3i-9